Question

Factorise: y² +7y+12.


Solve it!

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Answer 1

Answer:

The answer is $(y+3)(y+4)$

Step-by-step explanation:

  $y^2+7y+12$

$=y^2+3y+4y+12$, Split the middle term

$=(y^2+3y)+(4y+12)$, Group the terms

$=y(y+3)+4(y+3)\\=(y+3)(y+4)$

Answer 2

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${Y}^{2} - 7y + 12$

$=Y2−3y−4Y+12$

$=Y(Y−3)−4(Y−3)$

$=(Y−3)(Y−4)$

⇒Y−3 is a factor of Y2−7Y+12