Question

Factorise :ycube-6y square +3y +10 if y+1 is a factor of it

Answer 1

Answer: (y+1)(y-2)(y-5)

Step-by-step explanation:

y^3 -6y^2+3y+10

(y+1)(y^2-7y+10)

(y+1)(y-2)(y-5)

And that's it... Hope it Helped all...:-)

Answer 2

Answer:

(y-2),(y-5) are two other factors

Step-by-step explanation:

as y+1 is one factor of y^3 -6y^2 +3y+10=0

-1 is a root of  y^3 -6y^2 +3y+10=0

product of roots a,b,c is 10

sum of roots is 6

abc=10  ,a+b+c=6

let a=-1

then bc=-10    , b+c= 7

b=-10/c

-10/c+c=7

solving above equation we get roots as 2,5,-1