Question

Find the quadratic polynomial the sum of whose zeroes is -5 and their product ia 6 find the zeroes of polynomial​

Answer 1

Answer:

Hello Dear User__________

Here is Your Answer...!!

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Step by step solution:

$Given \ \alpha +\beta =-5\\\\and \ \alpha \beta=6\\ \\For \ required \ polynomial=x^{2} -(\alpha+\beta )x+\alpha \beta\\\\Require \ polynomial =x^{2} +5x+6\\\\Now \ factorize \ it \ x^{2} +5x+6\\\\x^{2}+3x+2x+6\\\\x(x+3)+2(x+3)\\\\(x+3)(x+2)\\\\x=-3 \ or \ x=-2\\\\so \ zeroes \ are \ -3 \ and \ -2$

Hope it is clear to you.

Answer 2

Given :

• Sum of zeros = - 5

• Product of zeros = 6

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To Find :

• Quadratic Polynomial

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Solution :

⇒k[x² - (sum of zeros)x + Product]

⇒k[x² - (-5)x + 6]

⇒k[x² + 5x + 6]

⇒x² + 5x + 6

➜ Quadratic polynomial is x² + 5x + 6