Question

factorise : z²-7z+12​

Answer 1

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${z}^{2} - 7z + 12 \\ \\ = {z}^{2} - (4 + 3)z + 12 \\ \\ = {z}^{2} - 4z - 3z + 12 \\ \\ = z(z - 4) - 3(z - 4) \\ \\ = (z - 4)(z - 3)$

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Answer 2

Solution"

=z²-7z+12

=z²-4z-3z+12

=z(z-4)-3(z-4)

therefore,(z-4)(z-3)

hope its helpful

thanks