Question

factorise1/27x^3-y^3+125z^3+5xyz

Answer 1

Hi ,

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We know the algebraic identity,


a³ + b³ + c³ - 3abc

= (a+b+c)(a² + b² + c² - ab - bc - ca )

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(1/27) x³ - y³ + 125z³ + 5xyz

= (x/3)³+(-y)³+(5z)³ - 3×(x/3)(-y)(5z)

=(x/3-y+5z)[(x/3)²+(-y)²+(5z)²-(x/3)(-y)-(-y)(5z)-(5z)(x/3)]

=(x/3-y+5z)[x²/9-y²+25z²+xy/3+5yz-5zx/3 ]

I hope this helps you.

: )

Answer 2

Hi,

Please see the attached file!



Thanks