Math, asked by sonusachdeva321, 11 months ago

factorise4y3-2y2-4y+2​

Answers

Answered by rishikapaul69
1

4y ^{3}  - 2 y^{2}  - 4y + 2

2y ^{2} (2y - 1) - 2(2y - 1)

(2y ^{2}  - 2)(2y - 1)

2(y ^{2}  - 1)(2y - 1)

2(y + 1)(y - 1)(2y - 1)


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Answered by Anonymous
0

Answer:

 {4y}^{3}  -  {2y}^{2}  - 4y + 2 \\  \\  {2y}^{2} (2y - 1) - 2(2y - 1) \\  \\ ( {2y}^{2}  - 2)(2y - 1)

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