factorise8xcube_1/27 y cube
indusinghkancha:
8X^3×1/27Y^3
Is this the question
8X^3+1/27Y^3
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8X^3+1/27Y^3
=(2X)^3+(1/3Y)^3
=(2X+3Y)[(2X)^2+(2X)(1/3Y)+(1/3Y)^2]
=(2X+3Y)(4X^2+2/3XY+1/9Y^2]
(ANSWER)
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=(2X)^3+(1/3Y)^3
=(2X+3Y)[(2X)^2+(2X)(1/3Y)+(1/3Y)^2]
=(2X+3Y)(4X^2+2/3XY+1/9Y^2]
(ANSWER)
#Mark as the Brainliest
Regards
Team Kancha
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