Question

Factorised form of x²-4x-45 is​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$\huge\mathcal{solution}$

$\mathcal\purple{factorise \: {x}^{2} - 4x - 45}$

To find two numbers whose product is (-45) and the sum is (-4)

: . The product is negative

: . One of the numbers is positive and the other number is negative

: . Sum is negative , therefore , the numerically greater of the two numbers is negative

So the required numbers are (-9) and 5 .

$\huge\mathtt\red{ {x}^{2} - 4x - 45}$

$\sf\purple{ {x }^{2} + ( - 9 + 5)x - 45 }$

$\sf\purple{ {x}^{2} - 9x + 5x - 45}$

$\sf\purple{x(x - 9) + 5(x - 9)}$

$\sf\purple{(x - 9)(x + 5)}$

Step-by-step explanation:

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