Question

factorisethe following using identities 1 + a + ab + a2b​

Answer 1

$\: \: \: \: 1 + a + ab + {a}^{2} b \\ = > 1(1 + a) + ab(1 + a) \\ = > (1 + a)(1 + ab)$

HOPE ITS HELPS U..

PLZ MARKS AS BRAINLIEST..

Answer 2

Answer:

1 + a + ab + a^2b

1 ( 1 + a ) + ab ( 1 + a )

( 1 + a ) ( 1 + ab )

hope it helps you