Question

Factorisex^12-y^12 in a easy way

Answer 1

hey friend here is ur answer

Answer 2

[0010001111]... Hello User... [1001010101]
Here's your answer...
${x}^{12} - {y}^{12} \\ = ( {x}^{6} + {y}^{6} )( {x}^{6} - {y}^{6} ) \\ = ({x}^{6} + {y}^{6} )( {x}^{3} + {y}^{3} )( {x}^{3} - {y}^{3} ) \\ = ( {x}^{6} + {y}^{6} )(x + y)( {x}^{2} - xy + {y}^{2} )(x - y)( {x}^{2} + xy + {y}^{2} )$

Here we used the following identities:
x²-y² = (x+y) (x-y)
x³+y³ = (x+y) (x²-xy+y²)
x³-y³ = (x-y) (x²+xy+y²)

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