Question

factorising expression by grouping 2x-xy+4y-8​

Answer 1

Answer:

X(2-y)+4(y-2)

Step-by-step explanation:

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First we see the question=2xy-xy+4y-8

We divide it into two groups=2x-xy and 4y-8

Now factorise it=case1=X is common in 2x-xy, so it will be x(2-y)

Case2 =4 is common in 4y-8, so it will be 4(y-2)

The equation will be case1 + Case2

X(2-y)+4(y-2)