Question

factorixe using algebraic identity a^4-16​

Answer 1

Answer:

(a-2)(a+2)(a^2+4^2)

Step-by-step explanation:

a^4-16

=(a^2)^2-(4^)2.

now it has come in the form of a^2-b^2

& we know that a^2-b^2= (a+b)(a-b)

applying it we get,

(a^2-4^2)(a^2+4^2).....................(1)

then again by breaking (a^2-4^2) as it is also in the form of a^2-b^2

we get..,

(a-2)(a+2)......................(2)

now putting the value of (a^2-4^2) from eq 2 in eq 1 we got our final answer as....

(a-2)(a+2)(a^2+4^2)............

HOPE IT HELPS YOU.........

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Answer 2

Hope the answer helps

Step-by-step explanation:

a^4-16

=a^4-4^4

=(a^2)^2-(2^2)^2

=(a^2+2^2)(a^2-2^2)