Question

factorization 1/36a^2-
9/49b^2c^2​

Answer 1

Answer:

Step-by-step explanation:

In this question we known that:36,9,49 have their square root of 36 as 6

9 as 3 and 49 as 7

so by this we can write

(1/6a)²-(3/7bc)²

again we known that we have a factorization identity⇒a²-b²=(a+b)(a-b)

by putting the identity we get

(1/6a+3/7bc)(1/6a-3/7bc) is the answer

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