pleasssssanswer this question!!!!!!there is a triangular park ABC whose 2 corner angles A and B are 50 degree and 60 degree respectively.3 friends rashmi,sita,geetha go daily on morning walk and walk along these 3 sides AB,BC and AC Respectively.who walks maximum distance among these 3?who walks least? why morning walk is necessary for us?
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Answered by
4
The person who walks in the road AB walks the most. The person who walks in the road BC walks the least. Morning Walk makes us fit and active and ready for each action.
AsitAsmitSahu17:
and side opposite to least angle is smallest
this is one of the inequalities of triangle
thats ok...in this question we have to name a person who walks maximum...so how to find that...
rashmi maximum and sita minimum
sorry to ask but how?
Read the inequalities i sent above
sorry i understood the sum..
kkk
anyways thank you so much....
kk
Answered by
12
Answer:
In triangle ABC,
<A = 50° , <B = 60° , <C = ?
⇒ Sum of the angles of a triangle = 180°
50° + 60° + <C = 180°
110° + <C = 180° <C = 180° - 110°
∴ <C = 70°
Side AB is opposite to <C which is the maximum angle amongst other two angles ,
So, Rashmi walks the maximum distance AB.
Sita walks along side BC which is opposite to smallest angle A = 50° means Sita walks minimum distance of triangular ABC.
Morning walk is important for us as it keeps us fit and active throughout the day.
pls mark me the brainliest :)
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