Question

factorization
4x(square)-y(square)+4y-4

Answer 1

4 (x square-ysquare+y-1) =0. then 0×4 =0 so equation is xsquare -y (y-1)

Answer 2

$\huge\bold\blue{Solution : }$

$=\bold{ {4x}^{2} - {y}^{2} + 4y - 4} \\ \\ \bold{=4x {}^{2} - ( {y}^{2} - 4y + 4)} \\ \\ \bold{= (2 {x)}^{2} - ( {y}^{2} - 2.y.2 + {2}^{2} )} \\ \\\bold{ = (2x) {}^{2} - (y - 2) {}^{2} }\\ \\ \bold{= (2x - y + 2)(2x + y - 2)}$