Question

Factorization if 16x²-94x-126=0

Answer 1

Answer:

brother it's simple but first see the equation by discriminant formula and know the nature of roots i.e the roots will be real or not real

=> D=b^2-4ac

=> (-94)^2-4(16)(-126)

=> 8836+8064

=> 16900

therefore, D>0

therefore roots are real and distinct roots

here, this equation u cannot solve it by factorisation method so use quadratic formula

-b±✓b^2-4ac/2a

=> -(-94)±✓(-94)-4(16)(-126)/2(16)

=> 94±✓8836+8064/32

=> 94+✓16900/32

=> 94+130/32

=> 224/32 = 7

NOW, TAKE (-VE) SIGN

=> 94-130/32

=> -36/32 = -1.125

therefore roots are 7 and -1.125

THANK U