Question

Factorization method
Solve the following quadratic equation
X square + 5 x minus 6 equals to zero

Answer 1

Question :

Solve the following quadratic equation  :

   => x² + 5x - 6

Answer :

x = 1,-6

Given :

quadratic equation = x² + 5x - 6 = 0

To find :

zeroes of the quadratic equation

Solution :

 Given quadratic equation,

       x² + 5x - 6

To solve it using factorization method,

 we must know the sum - product pattern

• x² + 5x - 6

=> It is of the form ax² + bx + c

Find the product of quadratic term [ax²] and constant term [c]

=  x² × (-6)

= -6x²

Now, find the factors of "-6x²" in pairs

$=> x \times (-6x) \\\\ => -x \times 6x \\\\ =>2x \times -3x \\\\ => -2x \times 3x$

Now, from the above, find the pair that adds to get linear term [bx]

6x - x = 5x

So, split 5x into 6x and -x

    x² + 5x - 6 = 0

  x² - x + 6x - 6 = 0

Find the common factor,

 x(x - 1) + 6(x - 1) = 0

   (x - 1)(x + 6) =0

=> x - 1 = 0 ; x = 1

=> x + 6 = 0 ; x = -6

Answer 2

Kindly refer the attachment.........