factorization of (2a-b)(2a-b)+2(2a-b)-8
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Solution:
By factoring:
(2a-b)(2a-b)+2(2a-b)-8
We should get the common among the equation,
(2a-b)[(2a-b)+2]-8.
Therefore, factorization of (2a-b)(2a-b)+2(2a-b)-8 is (2a-b)[(2a-b)+2]-8.
By factoring:
(2a-b)(2a-b)+2(2a-b)-8
We should get the common among the equation,
(2a-b)[(2a-b)+2]-8.
Therefore, factorization of (2a-b)(2a-b)+2(2a-b)-8 is (2a-b)[(2a-b)+2]-8.
vivek566:
your answer is not right
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