factorization of 2x^2-3x+4
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2x²-3x+4=0 .... (Given quadratic equation)
comparing the above equation with ax² + bx+c=0
a=2, b=-3 and c=4
therefore,
b²-4ac=(-3) ²-4×2×4
=9-32
=-23
x=-b±√b²-4ac/2a
=3±√-23/4
therefore, x=3+√-23/4 or 3-√-23/4
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