Question

factorize 1/16x^2-1/169​

Answer 1

SOLUTION

TO FACTORISE

$\displaystyle \sf{ \frac{1}{16 {x}^{2} } - \frac{1}{169} }$

FORMULA TO BE IMPLEMENTED

We are aware of the identity that

$\displaystyle \sf{ {a}^{2} - {b}^{2} = (a + b)(a - b)}$

EVALUATION

$\displaystyle \sf{ \frac{1}{16 {x}^{2} } - \frac{1}{169} }$

$\displaystyle \sf{ = { \bigg( \frac{1}{4x} \bigg)}^{2} - { \bigg( \frac{1}{13} \bigg)}^{2} }$

$\displaystyle \sf{ = { \bigg( \frac{1}{4x} + \frac{1}{13} \bigg)} { \bigg( \frac{1}{4x} - \frac{1}{13} \bigg)} }$

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Answer 2

the answer is

factorize the following

1. the answer is
2. (1/4x + 1/13) ( 1/4x - 1/13 )