Question

Factorize 1/3x² - 2x - 9​

Answer 1

Question:

Factorize: x²/3 - 2x - 9

Answer:

(1/3)•(x - 9)(x + 3)

or

(x/3 - 3)(x + 3)

or

(x - 9)(x/3 + 1)

Solution:

The given polynomial is : x²/3 - 2x - 9

Now,

=> x²/3 - 2x - 9

=> (x² - 6x - 27)/3

=> (1/3)•(x² - 6x - 27)

=> (1/3)•[x² - 9x + 3x - 27]

=> (1/3)•[x(x - 9) + 3(x - 9)]

=> (1/3)•(x - 9)(x + 3)

or

(x/3 - 3)(x + 3)

or

(x - 9)(x/3 + 1)

Moreover,

For zeros of the polynomial, we have ;

=> (1/3)(x - 9)(x + 3) = 0

=> (x - 9)(x + 3) = 0

=> x = 9 , -3