Factorize:
1. a(a-1)-b(b-1).
And
2. P=2-a, prove that a^2+6ap+p^3-8=0
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1. a(a-1)-b(b-1)
=a^2-a-b^2-b
=a^2-b^2-a-b
=(a+b)(a-b)-1(a+b)
=-1(a+b)^2(a-b) ( Ans )
2.
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