Math, asked by Justalearner, 11 months ago

Factorize:
1. a(a-1)-b(b-1).
And
2. P=2-a, prove that a^2+6ap+p^3-8=0

Answers

Answered by chsrinivasrao7168
0

Answer:

0 is the answer of this question

Answered by Perseus453
0

1. a(a-1)-b(b-1)

=a^2-a-b^2-b

=a^2-b^2-a-b

=(a+b)(a-b)-1(a+b)

=-1(a+b)^2(a-b) ( Ans )

2.

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