Math, asked by palaksinghania08, 5 months ago

factorize 100x2 - 80xy + 16y2​

Answers

Answered by vimalmaurya0011
6

Answer:

100 {x}^{2}  - 80xy + 16 {y}^{2}  \\ (10x {)}^{2}  - 2(10x)(4y) + (4y {)}^{2}  \\  {(10 - 4y)}^{2}

Answered by Anonymous
6

 \huge \sf \underline \red{Answer : }

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \tt \underline{(  10x - 4y)(10x - 4y)}

 \huge \sf \underline \pink{Given : }

Factorize 100x² - 80xy +16y²

 \huge \sf \underline \blue{solution : }

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \rm{100 {x}^{2} - 80xy + 16 {y}^{2}}

 \:  \:  \:  \:  \:  \star \sf \underline{ \: we \: know \: that \: identity}

  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \bf{ \boxed{ \underline{ \underline{ \red{ \tt{ {a}^{2}  - 2ab +  {b}^{2} \: }}}}}}

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \rm{=(  10 {x)}^{2} - 2(10x)(4y) + (4y) {}^{2}  }

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \rm{ = (10x = 4y) {}^{2} }

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \rm{=( 10x - 4y)(10x - 4y)}

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