Question

factorize :- 15(x-2y)^2 - 8(x-2y) - 16

Answer 1

Answer:

15(x−2y)

2

−8(x−2y)−16

let x-2y=p then,

15(x−2y)

2

−8(x−2y)−16=15p

2

−8p−16

=15p

2

+12p−20p−16

=3p(5p+4)−4(5p+4)

=(5p+4)(3p−4)

Substituting p=x-2y we get

=[5(x−2y)+4][3(x−2y)−4]

=(5x−10y+4)(3x−6y−4)

Step-by-step explanation:

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Answer 2

Answer:

=(5x−10y+4)(3x−6y−4)

Step-by-step explanation:

15(x−2y)² −8(x−2y)−16

let x-2y=p then,

15(x−2y)² −8(x−2y)−16=15p²−8p−16

$= 15p{}^{2} + 12p - 20p - 16$

$=3p(5p+4) - 4(5p + 4)$

$=(5p+4)(3p - 4)$

Substituting p=x-2y we get

=[5(x−2y)+4][3(x−2y)−4]

=(5x−10y+4)(3x−6y−4)