Math, asked by blaeee, 1 year ago

factorize 16a to the power 7 - 54ab to the power 6

Answers

Answered by rakeshmohata
2
Hope u like my process
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Formula to be used :
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x³ - y³ = (x-y) (x² + xy +y²)
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16 {a}^{7}  - 54a {b}^{6}  \\  = 2a(8 {a}^{6}  - 27 {b}^{6} ) \\  = 2a((2 {a}^{2})^{3}   -  {(3 {b}^{2} )}^{3} ) \\  = 2a(2 {a}^{2}  - 3 {b}^{2} )( {(2 {a}^{2} )}^{2}  + 2 {a}^{2}  \times 3 {b}^{2}  +  {(3 {b}^{2}) }^{2}) \\  = 2a(2 {a}^{2}   - 3 {b}^{2} )(4 {a}^{4}  + 6 {a}^{2}  {b}^{2}  + 9 {b}^{4} )
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Hope this is ur required answer

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