Question

Factorize 16x2-81y2
Plz help me can you solve this question

Answer 1

Step-by-step explanation:

${16x}^{2} - {81x}^{2}$

$(4 \times 4) {x}^{2} - (9 \times 9) {x}^{2}$

$(4 \times 4 \times x \times x) - (9 \times 9 \times x \times x)$

$(4x)^{2} - (9x) ^{2}$

Hope it helps you:)

Answer 2

Rewrite 81y2 81 y 2 as (9y)2 ( 9 y ) 2 . Since both terms are perfect squares, factor using the difference of squares formula, a2−b2=(a+b)(a−b) a 2 - b 2 = ( a + b ) ( a - b ) where a=4x a = 4 x and b=9y b = 9 y .