Question

factorize 2(3x-4y)^2-3(3x-4y)-2

Answer 1

Step-by-step explanation:

Given,

2(3x - 4y)² - 3(3x - 4y) - 2

Let 3x - 4y be x.

Now the simplified version of question is,

2x² - 3x - 2

= 2x² - 4x + 1x - 2

= 2x(x - 2) + 1(x - 2)

= (2x + 1)(x - 2)

Now simply replace x as it's original value.

(2x + 1)(x - 2)

= (6x - 8y + 1)(3y - 4y - 2)

Hope it helps!

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