Question

factorize:
2(3x+4y)²-6(3x+4y)​

Answer 1

Answer:

 (3x−4y)2−25z2

 =(3x−4y)2−(5z)2,     Using a2−b2=(a+b)(a−b)

=(3x−4y+5z)(3x−4y

Step-by-step explanation:

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Answer 2

2(3x + 4y)² - 6(3x + 4y) = 2(3x + 4y) (3x + 4y - 3)

Given :

The expression 2(3x + 4y)² - 6(3x + 4y)

To find :

To factorise the expression

Solution :

Step 1 of 2 :

Write down the given expression

The given expression is

2(3x + 4y)² - 6(3x + 4y)

Step 2 of 2 :

Factorise the expression

$\sf 2 {(3x + 4y)}^{2} - 6(3x + 4y)$

$\sf = 2 {(3x + 4y)}^{}(3x + 4y) - 2 \times 3 \times (3x + 4y)$

$\sf = 2 (3x + 4y) (3x + 4y - 3)$

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