Factorize 25(x-y)^2-4(x-4)^2
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Hi...☺
Here is your answer...✌
25 (x - y)² - 4 (x - 4)²
= 5²(x - y)² - 2²(x - 4)²
= [ 5(x - y) ]² - [ 2(x - 4) ]²
= (5x - 5y)² - (2x - 8)²
= [(5x - 5y) + (2x - 8)] [(5x - 5y) - (2x - 8)]
[ using identity, a² - b² = (a + b) (a - b) ]
= (5x - 5y + 2x - 8) (5x - 5y - 2x + 8)
= (7x - 5y - 8) (3x - 5y + 8)
Here is your answer...✌
25 (x - y)² - 4 (x - 4)²
= 5²(x - y)² - 2²(x - 4)²
= [ 5(x - y) ]² - [ 2(x - 4) ]²
= (5x - 5y)² - (2x - 8)²
= [(5x - 5y) + (2x - 8)] [(5x - 5y) - (2x - 8)]
[ using identity, a² - b² = (a + b) (a - b) ]
= (5x - 5y + 2x - 8) (5x - 5y - 2x + 8)
= (7x - 5y - 8) (3x - 5y + 8)
jindaljj1:
Thanku
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