Question

Factorize 256a^8-b^8

Answer 1

Answer:

Step-by-step explanation:

Hi, my friend

$256a^{8} - b^{8} \\(256 = 2^{8})\\\\=> (2^{8}*a^{8}) - b^{8} \\\\=> (2a)^{8} - (b)^{8}\\=> ((2a)^{4})^{2} - ((b)^{4})^{2}$

It's in the form of a² - b² = (a + b)(a - b)

Hence

$((2a)^{4} - b^{4})((2a)^{4} + b^{4})\\=> (((2a)^{2})^{2} - (((b)^{2})^{2})((2a)^{4} + b^{4})$

Again the first term is in the form of a² - b² = (a + b)(a - b).

=> (2a² + b²)(2a² - b²)(2(a^4) + (b^4))

Hence this is your answer.

Harith

Maths Aryabhatta

Answer 2

Hey mate , here is ur answer...

please mark it as brilliant answer.