Question

Factorize:
25a2 - 962 + 12bc --4c2
In the given figure ABCD is​

Answer 1

Step-by-step explanation: (5a) ²-[(3b) ²+2*3b*2c+(2c) ²]

(5a) ² - (3b+2c) ²

(5a-3b+2c) (5a+3b+2c)

Answer 2

Given:

Factorise :

$25a^{2} -9b^2+12bc-4c^2$

To find:

Factorisation of $25a^{2} -9b^2+12bc-4c^2$

Solution :

$25a^{2} -9b^2+12bc-4c^2$

By formula we get:

=$(5a)^2-[(3b)^2+c\times3b \times 2c+(2c)^2]$

=$(5a)^2-(3b+2c)^2$

By formula we get:

$a^{2} -b^{2}$

=(a+b)(a-b)

Thus we get:

=(5a-3b+2c)(5a+3b+2c)

Therefore, $25a^{2} -9b^2+12bc-4c^2$ = (5a-3b+2c)(5a+3b+2c)