Question

Factorize :27x^3+y^3+z^3-9xyz

Answer 1

27x3+y3+z3-9xyz

(3x)3+y3+z3-9xyz

(a3+b3+c3)=(a+b+c)(a2+b2+c2-ab-bc-cb)+3abc

a=3x

b=y

c=z

(3x+y+z)(9x2+y2+z2-3xy-yz-yz-3.3x.y.z)

(3x+y+z)(9x2+y2+z2-3xy-3xz-3xz)+3.3x.y.z-9xyz

(3x+y+z)(9x2+y2+z2-3xy-3xz-yz)

.9xyz and -9xyz both hv oppste sign so become zero

Answer 2

(3x)^3 + (y)^3 + (z)^3 - 3(3x)(y)(z)

(3x + y + z) (9x^2 + y^2 + z^2 - 3xy - yz - 3zx)