Question

factorize:27x3 + 8 b

Answer 1

Answer:

We know the identity a3−b3=(a−b)(a2+b2+ab)

Using the above identity, the equation 27x3−8 can be factorised as follows:

27x3−8=(3x)3−(2)3=(3x−2)[(3x)2+22+(3x×2)]=(3x−2)(9x2+4+6x)

Hence, 27x3−8=(3x−2)(9x2+4+6x)