Factorize (2a+3b+4c)^2
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Step-by-step explanation
(a+b+c)2 - a square + b square + c square + 2 a b + 2 BC + 2 CA
2 a ka square + 3 b square + 4 square
+ 2 into 2 into 3 + 2 into 3 into 4 + 2 into 4 c into 2 a
Full 1 square + 3 square + 16 secant squared plus 12 AB e plus 12 BC
plus 16 AC ka square
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Here your answer
(2a+3b+4c )^2
(2a)^2 +(3b)^2 +(4c)^2 +2 (2a)(3b) +2 (3b)(4c ) + 2 (4c)(2a)
4a^2 + 9b^2 + 16c^2 + 12ab + 24bc + 16ca
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