Factorize (2a+3b+4c)^2
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Answer:
(a+b+c)^2 = a^2+b^2+c^2+2ab+2bc+2ca
(2a+3b+4c)^2 = (2a)^2 + (3b)^2 + (4c)^2 + 2×2a×3b + 2×3a×4c + 2×4c×2a
= 4a^2 + 9b^2 + 16c^2 + 12ab + 24bc + 16ca
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Hey mate!
Answer refer to the attachment.
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