Question

Factorize (2a+3b+4c)^2

Answer 1

Answer:

(a+b+c)^2 = a^2+b^2+c^2+2ab+2bc+2ca

(2a+3b+4c)^2 = (2a)^2 + (3b)^2 + (4c)^2 + 2×2a×3b + 2×3a×4c + 2×4c×2a

= 4a^2 + 9b^2 + 16c^2 + 12ab + 24bc + 16ca

Answer 2

Hey mate!

Answer refer to the attachment.