Question

factorize 2ab-2b²+24ac-4bc using identities​

Answer 1

Answer:

( a2+b2) +2 _2 (ac+bd) x+ ( c2 +:d2 )= o has equaln roots there fore . discriminat =o

Thus (2c2+b2d2+)+4(a2+b2) (c2+d2) =>a 2c2 +2ac bd =a2+a2 d2 +

b2c2 +52 d2 =>( ad -bc) 2=o$ =ad- bc=o=> ad =bc