Question

A 1.0 m long metallic rod is rotated with an angular frequency of 400 rad s−1 about an axis normal to the rod passing through its one end. The other end of the rod is in contact with a circular metallic ring. A constant and uniform magnetic field of 0.5 T parallel to the axis exists everywhere. Calculate the emf developed between the centre and the ring.

Answer 1

The emf developed between the centre and the ring is 100 V.

Explanation:

Length of rod =1 m

Angular frequency "w" = 400 rad/s

Magnetic field "B" =0.5 T

Linear velocity at the fixed end = 0

Linear velocity at the other end =l x w

Average linear velocity = 0+lw / 2

                                      = lw / 2

e.m.f = Blv

        = Bl (lw / 2) = Bl^2 w / 2

        = 0.5×12×4002 = 100 V

Thus the emf developed between the centre and the ring is 100 V.

Also learn more

A particle moves in a circle of radius 20 cm with linear speed of 10 M per second the angular velocity of the particle particle is ?

https://brainly.in/question/7152887