Math, asked by dhriti30102003, 1 year ago

Factorize 2x^2+2√2x-15.

Answers

Answered by NightFury
3
 x =(2-√124)/-4=1/-2+1/2√ 31 = 2.284

 x =(2+√124)/-4=1/-2-1/2√ 31 = -3.284

Step by step solution :

Step  1  :

Equation at the end of step  1  :

((0 - 2x2) - 2x) + 15 = 0

Step  2  :

Step  3  :

Pulling out like terms :

 3.1     Pull out like factors :

   -2x2 - 2x + 15  =   -1 • (2x2 + 2x - 15) 

Trying to factor by splitting the middle term

 3.2     Factoring  2x2 + 2x - 15 

The first term is,  2x2  its coefficient is  2 .
The middle term is,  +2x  its coefficient is  2 .
The last term, "the constant", is  -15 

Step-1 : Multiply the coefficient of the first term by the constant   2 • -15 = -30 

Step-2 : Find two factors of  -30  whose sum equals the coefficient of the middle term, which is   2 .

     -30   +   1   =   -29     -15   +   2   =   -13     -10   +   3   =   -7     -6   +   5   =   -1     -5   +   6   =   1     -3   +   10   =   7     -2   +   15   =   13     -1   +   30   =   29
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