Question

factorize 2x^2+4y^2+3z^2+4 root 2 xy - 4 root 3 yz - 2 root 6 xz please answer

Answer 1

2x²+4y²+3z²+4√2xy-4√3yz-2√6xz

= (√2x)²+(2y)²+(√3z²)+2(√2)(2)+2(2)(√3)+2(√3)(√2)

= (√2x+2y-√3z)²

Hope it helps!!

Thank you ✌️

Answer 2

Answer:

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