factorize (2x-3)cube + (5x-2)cube
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arshiya21:
it was not correct but thanks for answering
okk
u know that anwer of this question
it's(7x-5) [19x²-51x+7]
then why r u ask the question
I am sure about this ans
Acha ji
Answered by
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(a-b)^3=a^3-b^3+3ab(a-b)
(2x-3)^3=8×x^3-27+3×2x×3(2x-3)
=8x3-27+36x2-54x
=8x3+36x2-54x-27
and
(5x-2)^3=125×x^3-8+3×5x×2(5x-2)
=125x3-8+30x(5x-2)
=125x3-8+150x2-60x
now add them we get
=133x3+186x2-114x-35
on simplification we get
x=(0.6290),
x=(-1.7944),
x=(-0.23312)
(2x-3)^3=8×x^3-27+3×2x×3(2x-3)
=8x3-27+36x2-54x
=8x3+36x2-54x-27
and
(5x-2)^3=125×x^3-8+3×5x×2(5x-2)
=125x3-8+30x(5x-2)
=125x3-8+150x2-60x
now add them we get
=133x3+186x2-114x-35
on simplification we get
x=(0.6290),
x=(-1.7944),
x=(-0.23312)
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