factorize= 2x²-9x+1
Answers
Here's the answer!
To Factorize:2x²+9x+10
=> {Firstly,to factorize a "quad eqn",you need to multiply the 1st and the 3rd term.Here,the number we obtain is 20. By factorizing it(using the prime division method),we have to find such a number that,while adding,gives us the number of the 2nd term. Here,we can use 5 and 4. By adding them,it's the second term,i.e,9. {9x} And when we multiply 5 and 4,we get 20.[As the product of the first and the last term is 20,in our quad eqn.] So,our factors are correct. }
Solution:-->
2x²+9x+10=0
(ax²+bx+c)=0 (A quadratic equation is always in this form.)
2x²+4x+5x+10=0 (Remember to take out the common terms from both the sides.
2x(x+2)+5(x+2)=0 (Make sure that the factors on the right side{x+2}are the same.)
(2x+5)(x+2)=0
when 2x+5=0
x=-5/2.
when x+2=0
x=-2.
So,the factors are:---> -5/2 and -2.
Hope that this helps!
this is not possible bro
the multiplication of 1st and last term's coefficient must be the number which has the product of middle term