Math, asked by harsh798313, 9 months ago

factorize= 2x²-9x+1​

Answers

Answered by Anonymous
0

Here's the answer!

To Factorize:2x²+9x+10

=> {Firstly,to factorize a "quad eqn",you need to multiply the 1st and the 3rd term.Here,the number we obtain is 20. By factorizing it(using the prime division method),we have to find such a number that,while adding,gives us the number of the 2nd term. Here,we can use 5 and 4. By adding them,it's the second term,i.e,9. {9x} And when we multiply 5 and 4,we get 20.[As the product of the first and the last term is 20,in our quad eqn.] So,our factors are correct. }

Solution:-->

2x²+9x+10=0

(ax²+bx+c)=0 (A quadratic equation is always in this form.)

2x²+4x+5x+10=0 (Remember to take out the common terms from both the sides.

2x(x+2)+5(x+2)=0  (Make sure that the factors on the right side{x+2}are the same.)

(2x+5)(x+2)=0

when 2x+5=0

x=-5/2.

when x+2=0

x=-2.

So,the factors are:---> -5/2 and -2.

Hope that this helps!

Answered by paramdholakia90757
0

this is not possible bro

the multiplication of 1st and last term's coefficient must be the number which has the product of middle term

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