Question

Factorize : 2x3 +128

Answer 1

Factor 2x^3+128

2x3+1282x3+128

Factor 22 out of 2x3+1282x3+128.

2(x3+64)2x3+64

Rewrite 6464 as 4343.

2(x3+43)2x3+43

Since both terms are perfect cubes, factorusing the sum of cubes formula, a3+b3=(a+b)(a2−ab+b2)a3+b3=a+ba2-ab+b2 where a=xa=x and b=4b=4.

2((x+4)(x2−x⋅4+42))2x+4x2-x⋅4+42

2(x+4)(x2−4x+16)

Answer 2

Hii here your answer

2x×3+128

=2 (x×3+64)

=2 (3x+64)


hope its help you