Factorize : 2x3 -128
Answers
Answered by
7
2x³-128
=2(x³-64)
=2(x³-4³)
=2(x-4)(x²+4x+16)
hope helped !
=2(x³-64)
=2(x³-4³)
=2(x-4)(x²+4x+16)
hope helped !
Answered by
2
2(x3−64)2x3-64
Rewrite 6464 as 4343.
2(x3−43)2x3-43
Since both terms are perfect cubes, factorising the difference of cubes formula, a3−b3=(a−b)(a2+ab+b2)a3-b3=a-ba2+ab+b2 where a=xa=x and b=4b=4.
2((x−4)(x2+x⋅4+42))2x-4x2+x⋅4+42
2(x−4)(x2+4x+16)
Rewrite 6464 as 4343.
2(x3−43)2x3-43
Since both terms are perfect cubes, factorising the difference of cubes formula, a3−b3=(a−b)(a2+ab+b2)a3-b3=a-ba2+ab+b2 where a=xa=x and b=4b=4.
2((x−4)(x2+x⋅4+42))2x-4x2+x⋅4+42
2(x−4)(x2+4x+16)
Similar questions