factorize 3ac+ 6ab+ 15a
Answers
Answered by
0
Answer:
How to solve your problem
+
8
3
=
2
3
y+\frac{8}{3}=\frac{2}{3}
y+38=32
Solve
1
Subtract
8
3
\frac{8}{3}
38
from both sides of the equation
+
8
3
=
2
3
y+\frac{8}{3}=\frac{2}{3}
y+38=32
+
8
3
−
8
3
=
2
3
−
8
Answered by
0
Answer:
3a(c+2b+5)
Step-by-step explanation:
It says factorize. So, we will have to divide all three of these terms by a common factor. As we see, 3a is present in all three terms. Hence, we take that common.
Divide 3ac by 3a. It results in c. So, in the bracket, the first term will be c.
Divide 6ab by 3a. It results in 2b. So, in the bracket, the second term will be +2b.
Divide 15a by 3a. It results in 5. So, in the bracket, the last term will be +5.
Hence, the total answer becomes,
3a(c+2b+5).
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