Question

factorize: 4(p + q) - 6(p + q)^2

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Answer 1

Step-by-step explanation:

4(p+q) - 6(p+q)²

2(p+q) [2 - 3(p+q) ]

now equating = 0

2(p+q) [2 - 3(p+q) ] = 0

2(p+q) = 0 and 2 - 3(p+q) = 0

p + q = 0 and 3(p+q) = 2

p = - q and 3p + 3q = 2