Question

factorize.40+3x-x^2.please send answer

Answer 1

Hey!!....Here is ur answer

40+3x-x^2

=> -(x^2-3x-40)

=> -(x^2-8x+5x-40)

=> -[ x (x-8)+5 (x-8)]

=> -(x-8)(x+5)

Hope it will help you

Answer 2

$40 + 3x - {x}^{2} = 0 \\ - {x}^{2} + 3x + 40 = 0 \\ factors \: are \\ - {x}^{2} - 5x + 8x + 40 = 0 \\ - x(x + 5) + 8(x + 5) = 0 \\ ( - x + 8)(x + 5) = 0 \\ x = 8 \\ x = - 5 \: are \: the \: factors \: of \: the \: given \: eq$