Question

factorize (4a+3b)^ - 4c^ ( use identities)

Answer 1

$(4a+3b)^2-4c^2$

$= (4a+3b)^2-2^2c^2$

$= (4a+3b)^2-(2c)^2$

using identity $x^2y^2=(xy)^2$

$= (4a+3b+2c)(4a+3b-2c)$

using identity $x^2-y^2=(x+y)(x-y)$

Hence final answer is (4a+3b+2c)(4a+3b-2c).