Question

Factorize 4x^2+24x+20​

Answer 1

=> 4x^2+24x+20.

=> 4(x^2+6x+5)=0

=> x^2+6x+5=0

=> x^2+3x+2x+5=0

=> x(x+3)+2(x+3)=0

★ (x+2)(x+3)

[x=-2 and x=-3]

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Answer 2

Question:

$4x^{2} + 24x + 20$

Concept:

$\text{By middle- Splitting factor theorem}$

Solution:

• LCM of 4 × 20 i.e. 80 is 2 × 2 × 2 × 5 × 2

So the equation formed is;

$4x^{2} + (20 + 4)x + 20$

$4x^{2} + 20x + 4x + 20$

$4x(x + 5) + 4(x + 5)$

Taking the common's, we get the equation as.

$(x + 5)(4x + 4)$

Hence the value of x is

• x + 5 = 0

x = -5

• 4x + 4 = 0

4x = -4

x = -1

$\text{Hence the value of x is -5 \& -1...}$