Question

Factorize (4y-5)^2+80​

Answer 1

Answer:

we know that (a-b)^2= a^2+b^2-2×a×b

..............please mark it as brainleast ans.

Answer 2

Step-by-step explanation:

(4y-5)^2+80=0

(4y-5)^2=-80

4y-5= √-80

4y-5= +-4√5i

4y=5+-4√5i

y=5+4√5i and y=5-4√5i