Question

factorize:59×59×59-9×9×9÷59×59+59×9+9×9=50

Answer 1

let a=59
b=9

a^3-b^3/a^2+ab+b^2
(a-b)(a^2-ab+b^2)/(a^2-ab+b^2)
then (a-b)
59-9=50
hope this help you
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Answer 2

Answer:

$\red { 59\times 59 \times 59-9\times 9 \times 9\div 59\times 59+59\times 9 + 9\times 9 }= \green {50}$

Step-by-step explanation:

$LHS =\red { 59\times 59 \times 59-9\times 9 \times 9\div 59\times 59+59\times 9 + 9\times 9 }$

$= \frac{59^{3}-9^{3}}{59^{2}+58\times 9 + 9^{2}}$

$Let \: \blue {a = 59, \: b = 9 }$

$=\frac{a^{3}-b^{3}}{a^{2}+ab+b^{2}}$

$= \frac{(a-b)(a^{2}+ab+b^{2})}{a^{2}+ab+b^{2}}$

$= a-b\\=\blue { 59-9}\\=\green {50}\\=RHS$

Therefore.,

$\red { 59\times 59 \times 59-9\times 9 \times 9\div 59\times 59+59\times 9 + 9\times 9 }= \green {50}$

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